Решение задачи: Сокращение дробей (Карточка №41)

Карточка № 41. Сократите дроби: 1) \(\frac{27}{36} = \frac{27 : 9}{36 : 9} = \frac{3}{4}\) 2) \(\frac{28}{35} = \frac{28 : 7}{35 : 7} = \frac{4}{5}\) 3) \(\frac{50}{75} = \frac{50 : 25}{75 : 25} = \frac{2}{3}\) 4) \(\frac{44}{88} = \frac{44 : 44}{88 : 44} = \frac{1}{2}\) 5) \(\frac{112}{80} = \frac{112 : 16}{80 : 16} = \frac{7}{5} = 1\frac{2}{5}\) 6) \(\frac{105}{30} = \frac{105 : 15}{30 : 15} = \frac{7}{2} = 3\frac{1}{2}\) 7) \(\frac{6 \cdot 25}{35 \cdot 8} = \frac{3 \cdot 2 \cdot 5 \cdot 5}{7 \cdot 5 \cdot 4 \cdot 2} = \frac{3 \cdot 5}{7 \cdot 4} = \frac{15}{28}\) 8) \(\frac{2 \cdot 9 \cdot 12}{6 \cdot 8 \cdot 3} = \frac{2 \cdot 9 \cdot 12}{18 \cdot 8} = \frac{2 \cdot 9 \cdot 4 \cdot 3}{9 \cdot 2 \cdot 4 \cdot 2} = \frac{3}{2} = 1\frac{1}{2}\) 9) \(\frac{18 \cdot 42 \cdot 15}{49 \cdot 20 \cdot 27} = \frac{(9 \cdot 2) \cdot (7 \cdot 6) \cdot (5 \cdot 3)}{(7 \cdot 7) \cdot (5 \cdot 4) \cdot (9 \cdot 3)} = \frac{2 \cdot 6}{7 \cdot 4} = \frac{12}{28} = \frac{3}{7}\)